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BiologyExchange surfaces and gas exchange › Three other answers: tracheae, gills and stomata

Three other answers: tracheae, gills and stomata

An insect delivers air to its cells and never bothers loading it onto blood. A fish runs water past its blood in the opposite direction and strips out four fifths of the oxygen. A leaf leaves the door open and pays in water. Each is a different reading of the same problem.

Before this Surface area to volume ratio and Fick's law · Water potential and osmosis

Before you start

A fish's gills work well because water flows over a huge surface area, so plenty of oxygen has the chance to diffuse across. The area is real, and on its own it would not save the fish. Run water and blood the same way along a lamella and they equalise part-way along, after which the remaining surface does nothing at all, however large it is. What makes a gill work is that the water and the blood travel in opposite directions, so the water alongside any point on the lamella is always richer in oxygen than the blood beneath it. The gradient is the adaptation. The area only becomes useful once there is a gradient everywhere along it.

What you should be able to do

Insects: air to the cell, not to the blood

An insect has a waterproof exoskeleton, which solves the problem of drying out and creates the problem of getting oxygen through it. The solution is a system of tubes that pipes air directly to the tissues, so that the blood never has to carry oxygen at all.

Air enters through spiracles, pores along the thorax and abdomen, each guarded by valves and often fringed with hairs. From each spiracle a trachea runs inwards, held open by rings of chitin in its wall in the same way the trachea of a mammal is held open by cartilage. The tracheae branch repeatedly into tracheoles, which are under a micrometre across, have no chitin lining, and run between and even into the cells. Oxygen diffuses out through the tracheole wall straight into the cytoplasm, and carbon dioxide diffuses back the same way.

The tracheole ends are full of fluid at rest, and gases diffuse about ten thousand times more slowly through liquid than through air. What changes during activity is not the tubing but how much of it is full of water.

The fluid movement is a favourite exam question and it depends on water potential. During sustained activity a muscle cell respires anaerobically in part, and lactate accumulates in the cytoplasm. That lowers the water potential of the cell, so water moves out of the tracheole into the cell by osmosis. Air is drawn further along the tracheole to fill the space, the final stretch of the diffusion pathway is now gas rather than liquid, and oxygen reaches the cell far faster. The system tunes itself to demand without any control mechanism at all.

Diffusion is the main mechanism, but larger and more active insects supplement it. Rhythmic contraction of the abdominal muscles squeezes the tracheae and moves air along them in bulk, which is mass transport rather than diffusion. Some insects also close alternate spiracles in a co-ordinated pattern so that air is driven through the system in one direction.

Every open spiracle is also a hole through which water vapour leaves, and an insect is small enough to have a high surface area to volume ratio, so the loss matters. The spiracles are therefore kept shut when the insect is inactive and opened only as demand requires, the cuticle is waterproofed with wax, and the hairs around each spiracle hold a layer of humid air that shallows the gradient for water loss. That last point is the same trick a xerophyte uses, and it appears again at the end of this lesson.

The limit of the whole design is worth stating, because questions ask for it. Diffusion down a tracheal tube is slow over long distances, so the tracheal system sets a ceiling on insect body size. Insects were much larger in the Carboniferous, when the atmosphere held a substantially higher proportion of oxygen than it does now.

Fish: the direction of flow is the adaptation

Water is a difficult medium to breathe. A cubic decimetre of air holds around 210 cm³ of oxygen; the same volume of fresh water at 15 °C holds about 7 cm³, roughly thirty times less. Water is also about eight hundred times denser than air and far more viscous, so moving it over a surface costs a fish real energy. A gill has to be very good indeed to make that arithmetic work.

A bony fish has four gill arches on each side of its head, covered by a bony flap called the operculum. Each arch carries two rows of gill filaments, and each filament carries stacks of thin plates, the lamellae, set at right angles to it. The lamellae are where exchange happens: each is covered by a single layer of cells, contains a capillary network, and the stacking gives an enormous area in a small space.

Water is kept moving in one direction by a two-stage pump. The fish lowers the floor of its buccal cavity with the mouth open, which increases the volume, drops the pressure and draws water in. It then closes its mouth and raises the floor, raising the pressure and forcing water over the gills and out past the operculum, which opens as a valve on the way out. Water therefore flows continuously and in one direction, and never sloshes back and forth over a surface it has already stripped.

In the upper plot the two lines never meet, so a gradient exists at every point and diffusion continues along the whole lamella. In the lower plot the lines converge part-way along and everything after that point is wasted surface.

This is the mark scheme's favourite comparison, and there is a wrong way to say the right thing. Writing that counter-current flow 'maintains a concentration gradient' earns one mark. Writing that it maintains a concentration gradient along the whole length of the lamella, so that oxygen diffuses from water to blood across the entire surface rather than only the first part of it, earns the rest. The number usually quoted is that a bony fish removes about 80% of the dissolved oxygen from the water passing over its gills, against a theoretical ceiling of 50% for parallel flow.

Notice too what counter-current makes possible that sounds impossible: blood leaves the lamella with a higher oxygen content than the water leaving beside it. There is no contradiction, because that blood met its water at the opposite end, where the water was fresh. Parallel flow can never do this, since the best it can achieve is for both to end at the same value.

Gill filament
One of the many thin projections from a gill arch, sometimes called a primary lamella.
Lamella
One of the thin plates set at right angles along a gill filament, one cell thick and richly supplied with blood; the actual exchange surface.
Counter-current flow
An arrangement in which two fluids move past each other in opposite directions, so a concentration gradient is maintained along the whole length of the exchange surface.
Operculum
The bony flap covering the gills of a bony fish, acting as a valve and part of the pump that maintains the flow of water.

A gill out of water fails for a structural reason, not a chemical one. Water supports the lamellae and holds them apart; in air they stick together and collapse into a wet mass, so the surface area falls catastrophically. A stranded fish suffocates in an atmosphere containing thirty times more oxygen than the water it came from.

Leaves: the same hole for two jobs

A plant needs carbon dioxide in during the day and oxygen in at all times, and it has no muscles, no blood and nothing that could be called ventilation. It manages with pure diffusion, which works because a leaf is thin and full of holes.

Gas enters through stomata, pores in the epidermis, mostly on the lower surface of a typical broad leaf. Inside, the spongy mesophyll is a loose network of cells with large air spaces between them, so gas diffuses freely through the leaf's interior and reaches the moist surface of every mesophyll cell. Those wet cell walls are the exchange surface, and they add up to an area several times the area of the leaf itself. No cell in a leaf is more than a fraction of a millimetre from an air space, so the diffusion distance is short and no transport system for gases is needed at all.

Each stoma is bounded by two guard cells, and unlike every other exchange surface in this unit, it can be shut. When the plant has water to spare, potassium ions are actively pumped into the guard cells. The water potential of the guard cells falls, water follows by osmosis, and the cells become turgid. Because the wall facing the pore is thicker than the outer wall, and the cellulose microfibrils are arranged in hoops around the cell, the cell lengthens by curving rather than by swelling evenly. The two cells bow away from each other and the pore opens.

The two cells stay joined at their ends whatever they do, which is why an open stoma is lens-shaped rather than a straight slot. Reverse the ion movement and the whole thing runs backwards.

Reverse the process and the stoma shuts. Potassium ions leave, water follows, the guard cells go flaccid, and the pore closes. Plants shut their stomata in darkness, when photosynthesis has stopped and carbon dioxide is not wanted, and in drought, when the hormone abscisic acid is released from roots in dry soil and triggers closure.

The trade-off is unavoidable, and it is the point of the whole section. The leaf interior is saturated with water vapour while the air outside rarely is, so a pore open enough to let carbon dioxide in is open enough to let water vapour out. That loss is transpiration, and it is the reason a plant spends water it cannot always replace in order to feed itself.

Xerophytes: making the gradient shallow

A plant living where water is scarce cannot stop exchanging gases, so it attacks the other terms of Fick's law instead. Every classic xerophyte adaptation is doing one of three things: cutting the area available for loss, lengthening the diffusion pathway, or flattening the gradient by trapping humid air next to the pore.

Marram grass does all three at once, which is why it is the example boards keep coming back to. The rolled leaf shelters the stomata, the hairs hold still air against them, and the pits lengthen the path a water molecule has to take to escape.
AdaptationHow it reduces water lossExample
Thick waxy cuticleWaterproofs the epidermis so vapour can only leave through stomataHolly, cacti, marram grass
Stomata sunk in pitsTraps humid air in the pit, lowering the gradient and lengthening the pathwayMarram grass, pine needles
Hairs on the epidermisHold a layer of still, humid air against the surface, lowering the gradientMarram grass, many silver-leaved shrubs
Rolled leavesEncloses the stomata in a humid chamber and cuts the exposed surface areaMarram grass
Reduced leaves or spinesCuts the surface area available for evaporationCacti, gorse
Stomata open at night onlyRestricts loss to the coolest, most humid part of the dayCacti and other succulents

The mechanism behind the middle rows is one idea repeated. Water vapour leaving a stoma has to diffuse away from it, and if it cannot get away it accumulates and the air immediately outside the pore approaches saturation. The difference in water potential between the leaf interior and the air just outside then becomes small, and the rate of loss falls with it. Pits, hairs and rolled leaves are all ways of preventing the humid air near a stoma from being carried off by wind.

There is a cost, and good answers acknowledge it. Everything that slows water leaving also slows carbon dioxide entering, so a xerophyte's rate of photosynthesis is typically lower than that of a plant with unrestricted stomata. Succulents that open their stomata only at night, storing carbon dioxide as an organic acid until daylight, accept the same penalty in a different currency: the storage step costs energy and the daily supply is capped by how much acid the plant can hold.

Boards divide this content up differently, which matters when you revise. AQA 7402 examines insects, fish, leaves and xerophytes together in its gas exchange topic. OCR A H420 examines insects and fish under exchange surfaces but places stomata and xerophytes with transport in plants. Cambridge 9700 does not examine the insect tracheal system or the fish gill at all, and covers xerophyte adaptations within transport in plants. Check what your own board asks for before you spend an evening on gill arches.

TRY IT — Comparing two exchange systems

Explain why an insect can supply its flight muscles with oxygen without any oxygen-carrying pigment in its blood, while a fish of similar mass cannot manage without haemoglobin.

Check your answer

The insect's tracheal system delivers air directly to the tissues. Tracheoles run between and into the cells, so the diffusion distance from air to cytoplasm is only a fraction of a micrometre and no carrier is needed to bridge a gap.

Gases also diffuse far faster in air than in liquid, so a gas-filled tube is a much better delivery route than a liquid-filled one over the same distance. During activity the tracheal fluid withdraws and even more of the pathway becomes gas.

A fish takes oxygen up at a gill, which may be many centimetres from a working muscle. Diffusion time rises with the square of the distance, so diffusion alone would take far too long, and the oxygen has to be carried in a mass transport system instead. Blood plasma dissolves very little oxygen, so haemoglobin is needed to raise the amount each volume of blood can carry.

The comparison to draw out is that the insect solved the distance problem with plumbing and the fish solved it with a pump and a carrier. Both are answers to the same fact about diffusion over distance.

In the exam

Check yourself

Water flows over a gill lamella at a rate of 100 arbitrary units of oxygen per minute and leaves carrying 20. Blood arrives carrying 10 and leaves carrying 90. Show that these figures are consistent, state what would happen if the blood flow were reversed, and explain the difference in terms of the concentration gradient.

Answer

Check the balance first. The water loses 100 − 20 = 80 units and the blood gains 90 − 10 = 80 units. Whatever leaves one fluid enters the other, so the figures are consistent.

The blood leaves carrying 90 while the water leaves carrying 20, which looks impossible until you notice which end each fluid leaves from. Blood at 90 is leaving at the end where water arrives at 100, so it is beside water richer than itself right up to the moment it goes.

Reverse the blood flow and the two now travel the same way. They start far apart, 100 against 10, and converge as oxygen crosses. Once they reach the same value there is no gradient left and diffusion stops, so both leave at about 55 units and the rest of the lamella does nothing.

The reason is the gradient. In counter-current flow the water alongside any point of the lamella is always richer in oxygen than the blood at that point, so oxygen diffuses across the full length of the surface. In parallel flow the gradient exists only over the first part of the lamella and the remaining surface is wasted, which is why the counter-current arrangement extracts around 80% of the oxygen and the parallel one could not exceed half.

Questions

Written to the command words the boards use. Try them on paper before opening a scheme: the marks go to points made, not to length.

Question 14 marks

A bony fish removes about 80 per cent of the dissolved oxygen from the water passing over its gills, while parallel flow could not exceed 50 per cent. Explain this difference.

Mark scheme
  1. B1 in counter-current flow the water and the blood travel in opposite directions along the lamella
  2. B1 the water alongside any point on the lamella therefore always holds more oxygen than the blood beneath it
  3. B1 a concentration gradient is maintained along the whole length of the lamella, so oxygen diffuses into the blood across the entire exchange surface
  4. A1 in parallel flow the two fluids converge part-way along, and once they reach the same concentration diffusion stops and the rest of the surface is wasted, so at best both leave at about half the starting value

Question 24 marks

Describe what happens to the fluid at the ends of an insect's tracheoles during a period of sustained activity, and describe the effect this has on the delivery of oxygen.

Mark scheme
  1. B1 the muscle cells respire anaerobically in part, so lactate accumulates in their cytoplasm
  2. B1 the water potential of the muscle cells falls below that of the tracheal fluid
  3. B1 water therefore moves out of the end of the tracheole into the muscle cell by osmosis, and air is drawn further along the tracheole to fill the space
  4. A1 more of the final stretch of the pathway is now gas rather than liquid, and gases diffuse far faster through air than through water, so oxygen reaches the cell sooner

Question 34 marks

A leaf has no ventilation and no transport system for gases, yet it supplies every mesophyll cell with carbon dioxide. Explain how it manages this, and explain why the same arrangement costs the plant water.

Mark scheme
  1. B1 gas enters through the stomata into the large air spaces of the spongy mesophyll, so it diffuses freely through the interior of the leaf
  2. B1 no cell is more than a fraction of a millimetre from an air space, so the diffusion distance is short enough for diffusion alone to be fast enough
  3. B1 the moist walls of the mesophyll cells act as the exchange surface, and together they come to several times the area of the leaf itself
  4. A1 the leaf interior is saturated with water vapour while the air outside rarely is, so a pore open enough to admit carbon dioxide also lets water vapour diffuse out

Question 43 marks

A fish stranded on a riverbank dies of oxygen shortage in air containing about thirty times more oxygen than the water it came from. Suggest why.

Mark scheme
  1. B1 in water the lamellae are supported and held apart, but in air they stick together and collapse into a wet mass
  2. B1 the surface area available for gas exchange therefore falls sharply
  3. A1 rate of diffusion is proportional to surface area, so too little oxygen crosses into the blood however much is present in the air around the fish

Question 53 marks

Compare the way an insect delivers oxygen to its flight muscles with the way a bony fish delivers oxygen to its swimming muscles.

Mark scheme
  1. B1 the insect pipes oxygen as a gas along tracheae and tracheoles directly to the cells, whereas the fish takes oxygen up at the gill and carries it in the blood
  2. B1 insect blood transports no oxygen at all, whereas the fish depends on haemoglobin to raise the amount of oxygen each volume of blood can carry
  3. A1 the insect's diffusion distance from air to cytoplasm is under a micrometre, whereas the fish's gill may be many centimetres from a working muscle, so a mass transport system is unavoidable

Question 62 marks

State two features of a gill lamella, other than the direction in which water flows over it, that increase the rate at which oxygen enters the blood.

Mark scheme
  1. B1 each lamella is covered by a single layer of cells, so the diffusion pathway is very short
  2. B1 the lamellae are stacked in large numbers along each filament, giving a very large surface area; accept a capillary network inside each lamella that carries oxygen away and maintains the gradient

Worth remembering

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