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BiologyScientific method and quantitative biology › Handling data: units, scales, rates and uncertainty

Handling data: units, scales, rates and uncertainty

Biology's arithmetic is not difficult, and it is where marks are lost in bulk. Almost all of it comes down to four habits: carry the unit through every line, know where your significant figures came from, read a gradient rather than eyeball it, and say how sure you are.

Before this Standard form and indices from GCSE mathematics · Plotting a line graph with a suitable scale

Before you start

You give your answer to the same number of decimal places as the numbers in the question. Decimal places and significant figures are different things, and the rule attaches to the wrong one. Measure a leaf at 43 mm with a millimetre rule and you have two significant figures; write that in metres and it becomes 0.043 m, which has three decimal places and still two significant figures, because moving the point cannot improve the ruler. Significant figures record how well you measured. Decimal places record which unit you happened to use.

What you should be able to do

Units, prefixes and the ladder biology lives on

Biology spans about nine factors of ten between a membrane and a person, and it handles that span with prefixes rather than with long strings of zeros. Every prefix is a power of ten and every conversion is a multiplication, so the only thing that can go wrong is the direction.

PrefixSymbolMultiplierWhere you meet it
megaM10⁶Base pairs in a genome
kilok10³Kilojoules, kilopascals
decid10⁻¹dm³, which is a litre
centic10⁻²cm³, marked on every syringe
millim10⁻³mm, mg, mmol
microµ10⁻⁶µm for cells and organelles
nanon10⁻⁹nm for membranes and ribosomes

1 mm = 1000 µm    1 µm = 1000 nm    1 dm³ = 1000 cm³three conversions carry most of the marks in this topic

The habit that stops errors is writing the unit on every line of working rather than only on the answer: if the units either side of an equals sign do not match, you have found the mistake before the marker did. It also catches conversions done backwards. A micrometre is smaller than a millimetre, so a length in micrometres is a bigger number, and a conversion that made the number smaller went the wrong way.

The spacing is the point. A membrane and a plant cell differ by nearly ten thousand times, and only a logarithmic axis can show both without one of them collapsing into the baseline.

Standard form writes anything very small or very large as a value between 1 and 10 multiplied by a power of ten: 0.000 007 m becomes 7 × 10⁻⁶ m, and 128 000 becomes 1.28 × 10⁵. Two things go wrong with it. The first digit must lie between 1 and 10, so 12 × 10⁴ is the right size and not standard form. And a negative index means a small number, not a negative one — 10⁻⁶ is a millionth.

Getting a length into the unit an answer wants

A ribosome measures 25 nm across. Express this in micrometres, and in metres in standard form.

Nanometres to micrometres is a division by 1000, because a micrometre is a thousand times bigger: 25 ÷ 1000 = 0.025 µm. Micrometres to metres is another division by a million, giving 0.000 000 025 m.

In standard form that is 2.5 × 10⁻⁸ m. Count the places the point moved — eight — and check the sign: the number is small, so the index is negative.

Then check it against the ladder. A ribosome should land between a molecule at 10⁻⁹ m and a bacterium at 10⁻⁶ m, and it does.

Where significant figures come from

A calculator gives you ten digits. The measurement gave you two or three, and writing down the ten is a claim about your apparatus that is not true. Significant figures are not a formatting convention; they are a statement about how finely you measured.

Start with the instrument. A metre rule reads to the nearest millimetre, so a leaf measured as 43 mm is known to two significant figures and one measured as 143 mm to three. A balance reading 4.20 g has three, and the trailing zero is significant because the balance printed it — writing 4.2 g throws away information you were given.

Significant figures
The digits in a measurement that carry information about its size, counted from the first non-zero digit.
Leading zeros
Never significant. 0.0043 has two significant figures, because the zeros only locate the decimal point.
Trailing zeros after a decimal point
Always significant. 4.20 has three, and says the hundredths digit was measured.

The rule for a calculation is that the answer carries the same number of significant figures as the least precise measurement that went into it, so a rate found by dividing a volume known to two figures by a time known to four is known to two. Round at the end rather than in the middle, because rounding twice drags the answer away from where it belongs. Two things sit outside the rule: exact numbers — the 100 in a percentage, the number of discs you counted — impose no limit at all, and an instruction in the question about how many figures to give always wins.

Where the figures come from

A student collects 24 cm³ of oxygen in 20 s. Calculate the rate of oxygen production to an appropriate number of significant figures.

Rate is volume over time: 24 ÷ 20 = 1.2 cm³ per second. The volume and the time each carry two significant figures, so the answer is entitled to two: 1.2 cm³ s⁻¹.

Had the syringe read 24.0 cm³ and the clock 20.0 s, both would carry three and the answer would be written 1.20 cm³ s⁻¹ — the same number making a stronger claim, which is what a significant figure is for.

Ratios, percentages, and telling the two percentages apart

A ratio compares two quantities of the same kind by division, and because the units cancel it has none of its own. That single fact is why magnification is written ×12 000 and never ×12 000 µm, and why an Rf value can never exceed 1.

magnification = image size ÷ actual sizeboth sizes in the same unit, always, before you divide

A magnification from a scale bar

An electron micrograph carries a scale bar labelled 2 µm. The bar measures 25 mm on the page. A mitochondrion in the same image measures 30 mm along its long axis. Calculate the magnification of the micrograph and the actual length of the mitochondrion.

Put both lengths into the same unit first: the scale bar is 25 mm on the page, and 25 mm = 25 000 µm.

The bar is the one object whose real length you know, so use it: magnification = 25 000 ÷ 2 = ×12 500, with no unit after it.

For the mitochondrion, actual = image ÷ magnification. Its image is 30 mm = 30 000 µm, so 30 000 ÷ 12 500 = 2.4 µm.

Under time pressure there is a shortcut. The mitochondrion is 30/25 = 1.2 times as long as the bar, and the bar is 2 µm, so it is 1.2 × 2 = 2.4 µm — same answer, and one fewer place to drop a factor of a thousand.

The two percentages are different calculations answering different questions.

percentage change = (final − initial) ÷ initial × 100the denominator is where you started, and the sign is part of the answer

percentage difference = (difference between the two) ÷ (one of them) × 100and you must say which one you divided by

Percentage change follows one thing over time. Keep the sign: a chip that loses mass has changed by −10%, and writing 10% throws away the direction the investigation was about.

Percentage difference compares two separate things and hides a trap in the denominator. If a treated group has a mean of 24 and a control 20, the treated group is 20% higher than the control while the control is 16.7% lower than the treated group. Both are correct and they answer different questions, so say which value you divided by and prefer the control where there is one.

Notice what the percentage buys you. A chip going from 4.20 g to 3.78 g lost 0.42 g and a second going from 6.30 g to 5.67 g lost 0.63 g, which looks worse — and both changed by −10.0%. The two chips behaved identically, and only the percentage says so.

Rates are gradients

A rate is a change in something divided by the time it took, so its unit always ends in 'per unit time' and its value is always a gradient on a graph of that something against time. Both halves of that sentence are examined.

rate = change in the quantity ÷ time takenunits: cm³ s⁻¹, mg min⁻¹, bubbles per minute, arbitrary units per second

On a straight line the gradient is the rate, and any two points give it. Take them far apart — a triangle spanning most of the line is read more accurately than a small one — and take the values off the axes rather than counting squares. On a curve the gradient changes from moment to moment and you need a tangent: a straight line touching the curve at the point of interest and running along it rather than cutting across it. The gradient of the tangent is the rate at that instant.

Watch the tangent turn as it advances. A chord across the whole curve gives an average and always understates the early rate; the tangent at t = 0 is the initial rate, and it is the only one that reflects the conditions you set up.

The initial rate matters more than any other in enzyme work, and the reason is worth writing out in an answer. At t = 0 the substrate concentration is the one you chose, the product concentration is zero and nothing the enzyme made has inhibited it yet. Every later gradient reflects the conditions you set and however much substrate has since gone, so a rate measured at three minutes measures two things at once.

A gradient from a tangent

A tangent drawn to the curve above at t = 0 rises by 18 cm³ over a run of 20 s. Calculate the initial rate and state its units.

Gradient is rise over run: 18 ÷ 20 = 0.90 cm³ s⁻¹. Take both from the axes rather than the paper — a run measured in centimetres of graph paper means nothing.

The same construction at t = 50 s gives 4.0 cm³ over 20 s, or 0.20 cm³ s⁻¹, under a quarter of the initial rate because by then most of the substrate is gone. Neither number is wrong; they describe different moments.

There is a second route, used whenever the thing you can measure is a time. Time an amylase reaction until the iodine stops going blue-black, or a catalase-soaked paper disc until it floats, and the rate is 1 ÷ t, in units of per second. It works because the same amount of reaction has happened in every trial, so a shorter time is a faster reaction. The trap is plotting the time itself: a graph of time against temperature is upside down compared with a graph of rate against temperature, and one drawn that way and described the other way loses the whole question.

Why the axis is sometimes logarithmic

Two quantities in biology span so many factors of ten that a linear axis cannot show them, and both get a logarithmic one. On a logarithmic axis, equal distances represent equal multiplications rather than equal additions, so the steps 1, 10, 100, 1000 are evenly spaced.

Both panels contain the same nine counts. On the left, the first five hours are indistinguishable from zero and the curve tells you nothing about them; on the right, every hour is as readable as every other and the straight line says the growth factor never changed.

Population growth is the first case. A population doubling every hour from 500 cells reaches 128 000 in eight hours, and on a linear axis the first five hours lie flattened against the baseline where nothing can be read from them. Take the logarithm and the curve becomes a straight line, because each hour multiplies the population by the same factor and so adds the same amount to the logarithm. That the line is straight is itself the evidence that growth was exponential.

pH is the second, and it catches people out because the logarithm has a minus sign in front of it.

pH = −log₁₀[H⁺]so a lower pH means a higher hydrogen ion concentration

Each whole pH unit is a factor of ten in hydrogen ion concentration. Moving a buffer from pH 7 to pH 5 does not double anything; it multiplies the hydrogen ion concentration by a hundred, which is why an enzyme can be untouched at pH 7 and dead at pH 5, and why describing that change as 'a small change in pH' in an answer is wrong. The stomach at pH 2 holds a hydrogen ion concentration a hundred thousand times that of blood plasma at pH 7.

TRY IT — Reading a log axis

A culture is plotted with the logarithm to base 10 of the cell count on the vertical axis. The line is straight and rises from 3.0 at 0 hours to 6.0 at 10 hours. State the cell count at the start and at the end, and calculate how many times the population multiplied.

Check your answer

A logarithm of 3.0 means 10³, so the count started at 1000 cells per cm³, and 6.0 means 10⁶, so it finished at 1 000 000. The population multiplied 1000 times.

Notice the arithmetic. The logarithm rose by 3, and a rise of 3 on a log scale is a multiplication by 10³: subtracting on a log axis is dividing on the real one, which is the whole reason the axis is worth the trouble.

The line being straight adds something. The growth factor was constant across all ten hours, so nothing limited growth in that period.

Uncertainty, and how it travels through a calculation

Every measurement has an uncertainty: a range within which the true value lies. It is not a mistake and it is not an admission of carelessness. It is the width of what the instrument can tell you.

For a single reading off a scale, the uncertainty is usually taken as half the smallest division, so a millimetre rule gives ±0.5 mm. But a length is two readings, one at each end, so a measured length carries ±1 mm — and the same doubling applies to a thermometer read before and after or a burette read at start and finish. A digital instrument is quoted to its last displayed digit: a balance showing 4.20 g carries ±0.01 g.

percentage uncertainty = uncertainty ÷ measurement × 100which is why the same instrument is precise on a big reading and poor on a small one

The bar on the right is the same balance as the two on the left. Nothing about the instrument changed; the quantity being measured got small, and that is enough.

Combining uncertainties follows two rules, and which one you use depends on the arithmetic you did:

What you didWhat happens to the uncertaintyExample
Added or subtracted two quantitiesAdd the absolute uncertainties4.62 g ± 0.01 and 4.20 g ± 0.01 give a difference of 0.42 g ± 0.02
Multiplied or divided two quantitiesAdd the percentage uncertainties24 cm³ ± 4.2% divided by 20 s ± 2.5% gives a rate carrying 6.7%
Multiplied by an exact numberThe percentage uncertainty is unchangedDoubling a reading doubles its absolute uncertainty and leaves the percentage alone

The subtraction rule is the one with teeth: subtracting two similar numbers keeps the whole of both uncertainties and throws away most of the value. That is why a percentage change built on a small mass change is far shakier than either weighing was, and why an osmosis investigation is designed with a long enough immersion to produce a change worth measuring.

Carrying an uncertainty through to a percentage change

A potato chip is weighed at 4.20 g and again, after an hour in distilled water, at 4.62 g, on a balance reading to ±0.01 g. Calculate the percentage change in mass and the uncertainty in it.

The change is 4.62 − 4.20 = 0.42 g, and the two absolute uncertainties add: ±0.01 + ±0.01 = ±0.02 g. So percentage change = 0.42 ÷ 4.20 × 100 = +10.0%, a gain, so water entered the cells by osmosis.

Now the uncertainties. The change of 0.42 g carries 0.02 ÷ 0.42 × 100 = 4.8%. The initial mass of 4.20 g carries 0.01 ÷ 4.20 × 100 = 0.24%. The two were divided, so the percentages add: 4.8 + 0.24 ≈ 5.0%.

5.0% of 10.0 is 0.5, so the result is +10.0% ± 0.5: a chip that gained between 9.5% and 10.5% of its mass. Two weighings each good to a quarter of one per cent gave an answer good only to five per cent, and the subtraction is where it went.

One last habit. When a calculation is finished, ask whether the answer is the right size for a living thing. A cell 2 mm across, a resting heart rate of 400 beats per minute, a respiration rate that would consume a mouse's body mass in oxygen every hour — these are arithmetic slips announcing themselves, and an order-of-magnitude check catches nearly all of them in seconds.

In the exam

Check yourself

A student measures the length of the coleoptile of ten seedlings with a millimetre rule, before and after three days of growth in the dark. One seedling measures 18 mm at the start and 27 mm at the end. Calculate the percentage change in length, the mean growth rate in mm per day, and the percentage uncertainty in the percentage change. State the answers to a sensible number of significant figures.

Answer

Percentage change: 27 − 18 = 9 mm, and 9 ÷ 18 × 100 = +50%, to two significant figures because both measurements carry two. Growth rate: 9 mm over 3 days = 3.0 mm per day, and the 3 days is counted rather than measured so it imposes no limit on the figures.

Uncertainty: a millimetre rule read at both ends gives ±1 mm on each length, so the difference of 9 mm carries ±2 mm, which is 2 ÷ 9 × 100 = 22%. The initial 18 mm carries 1 ÷ 18 × 100 = 5.6%. The two were divided, so the percentages add to about 28%.

The percentage change is therefore 50% ± 14 percentage points, somewhere between about 36% and 64%. That is a startlingly wide answer from two tidy-looking measurements, and it shows what to change: leaving the seedlings a week rather than three days gives a bigger difference and shrinks the percentage uncertainty without touching the ruler. Taking a mean of ten seedlings helps too, though it does nothing about a rule misread the same way every time.

Questions

Written to the command words the boards use. Try them on paper before opening a scheme: the marks go to points made, not to length.

Question 14 marks

A potato chip is weighed at 5.00 g, left in a sucrose solution for an hour and weighed again at 4.60 g, on a balance reading to plus or minus 0.01 g. Calculate the percentage change in mass, and calculate the percentage uncertainty in that percentage change.

Mark scheme
  1. M1 change in mass = 4.60 − 5.00 = −0.40 g, and because the two masses were subtracted the absolute uncertainties add to give plus or minus 0.02 g
  2. A1 percentage change = −0.40 ÷ 5.00 × 100 = −8.00 per cent, the sign showing that the chip lost mass
  3. M1 percentage uncertainty in the change = 0.02 ÷ 0.40 × 100 = 5.0 per cent, and in the initial mass = 0.01 ÷ 5.00 × 100 = 0.20 per cent
  4. A1 the two were divided, so the percentage uncertainties add: about 5.2 per cent

Question 24 marks

A bacterial culture is counted every hour for ten hours and the counts are plotted with the logarithm to base 10 of the count on the vertical axis. Explain why a logarithmic axis is used here, and explain what a straight line on such a plot tells you.

Mark scheme
  1. B1 a population that multiplies repeatedly spans several factors of ten, so on a linear axis the early counts lie flattened against the baseline where nothing can be read from them
  2. B1 on a logarithmic axis equal distances represent equal multiplications, so the steps 1, 10, 100 and 1000 are evenly spaced and every hour is as readable as every other
  3. B1 each hour multiplies the population by the same factor and therefore adds the same amount to the logarithm, so constant growth plots as a straight line
  4. B1 a straight line is therefore evidence that the growth factor never changed over that period, which is what exponential growth means, and a rise of 3 on the axis is a multiplication of the population by 1000

Question 33 marks

A student collects 24 cm³ of gas in 20.0 s and writes the rate as 1.2 cm³ s⁻¹. Explain why the answer is given to two significant figures, and explain why counting the decimal places in the measurements is the wrong guide.

Mark scheme
  1. B1 an answer carries the same number of significant figures as the least precise measurement that went into it, and the volume of 24 cm³ carries only two
  2. B1 significant figures record how finely the instrument measured, so writing more digits claims a precision the syringe never had
  3. B1 decimal places depend only on the unit chosen: 24 cm³ written as 0.024 dm³ has three decimal places and still two significant figures, because changing the unit cannot improve the measurement

Question 43 marks

A tangent is drawn at the origin of a curve of volume of oxygen collected against time. The tangent passes through the points (0 s, 2.0 cm³) and (30 s, 20.0 cm³). Calculate the initial rate of oxygen production and give its unit.

Mark scheme
  1. M1 the rate is the gradient of the tangent, which is the rise divided by the run, with both values read off the axes rather than counted in squares of paper
  2. M1 rise = 20.0 − 2.0 = 18.0 cm³ and run = 30 − 0 = 30 s
  3. A1 initial rate = 18.0 ÷ 30 = 0.60 cm³ s⁻¹

Question 53 marks

An osmosis investigation reports a percentage change in the mass of a potato chip carrying a percentage uncertainty of over 30 per cent, even though the balance reads to plus or minus 0.01 g. Suggest why the uncertainty is so large, and suggest one change to the method that would reduce it.

Mark scheme
  1. B1 the percentage change rests on the difference between two similar masses, and subtracting keeps the whole of both absolute uncertainties while leaving only a small value behind
  2. B1 so the percentage uncertainty in that small difference is large even though each individual weighing was good to a fraction of one per cent
  3. B1 leaving the chips immersed for longer, or using a solution further from the potato's own water potential, produces a larger change in mass and shrinks the percentage uncertainty without changing the balance

Question 62 marks

State what is meant by the resolution of a measuring instrument, and state the uncertainty carried by a single reading taken from a millimetre rule.

Mark scheme
  1. B1 resolution is the smallest change an instrument can register, such as 1 mm on a metre rule or 0.01 g on a two-decimal-place balance
  2. B1 a single reading off a scale is taken as half the smallest division, so plus or minus 0.5 mm

Worth remembering

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