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Radioactive decay and half-life

No nucleus knows its age and none can be hurried, yet a mole of them keeps time better than any clock. One constant, lambda, sets the odds; from it come the exponential, the half-life, and a straight-line log plot you have met once before.

Year 13AQA 3.8.1.3, 3.8.1.4CIE 11.1, 23.2OCR A 6.4.3

Builds on The time constant and exponential decay and Stable and unstable nuclei.

IN THIS TOPIC

  • Use λ, A = λN and the exponential decay equations, converting a mass to a number of nuclei when needed.
  • Determine a half-life from decay curves and from log graphs.
  • Predict the decay mode of a nuclide from its position on the N against Z graph and write the decay equation.

WHAT YOU PROBABLY THINK

After two half-lives, a sample has all gone.

Random for one, dependable for a mole

Radioactive decay is random: no measurement can tell you when a given nucleus will go, and nothing you do to it, heat, pressure, chemistry, changes its chances. What each nucleus has instead is a fixed decay constant λ, the probability of decaying per second. Model it with dice: each die has no memory, yet a large enough handful loses very nearly one sixth per throw.

With N undecayed nuclei each carrying probability λ per second, the expected rate of loss is

ΔNΔt = -λNON YOUR DATA SHEET

and the size of that rate is the activity A, in becquerels, one decay per second:

A = λNON YOUR DATA SHEET

Counting nuclei is chemistry's job. A mass m of a nuclide with molar mass M holds m/M moles, so N = (m/M) × NA nuclei, with the Avogadro constant from the data booklet. Exam questions lean on this chain often.

The exponential and its half-life

A rate of loss proportional to the amount remaining is the recipe you met with capacitor discharge, and it has the same solution:

N = N0e-λtON YOUR DATA SHEET
no nucleus knows its age; the population still obeys the lawtimeundecayed count N904523N₀ = 180, half-life 2.4 s in this loop
FIG. 1A hundred and eighty identical nuclei. Each decays at a random, unpredictable moment; watch any one and you learn nothing about when. Yet the count of survivors rides the smooth exponential, halving every half-life: 180, 90, 45, 23. The law belongs to the crowd, not to any nucleus in it.

The half-life is the time for N to halve. Set N = N0/2 and take logs: e-λT = 1/2 gives λT = ln 2, so

T½ = ln 2λON YOUR DATA SHEET

A big decay constant means a short half-life and a fierce source. Because activity is proportional to N, it decays with the same clock,

A = A0e-λtNOT ON THE DATA SHEET — LEARN IT

which is the form the detector sees. And the lie above answers itself: two half-lives leave a quarter, three an eighth. Halving forever never reaches nothing.

Reading decay data

From a decay curve, read the half-life directly: find the time for the activity to halve, then check it again from any other starting point; a genuine exponential halves in the same time everywhere along its length.

Take the natural log of the decay data and the exponential becomes a straight line whose gradient magnitude is the decay constantln Ntgradient = −λ
FIG. 2The log plot: ln N against t is a straight line with gradient minus lambda.

For scattered data the better tool is the promised twin of the capacitor practical. Taking natural logs gives ln N = ln N0 − λt, a straight line of ln N against t with gradient −λ. Straightness is the evidence the decay is exponential, and the gradient hands you λ, from which T½ = ln 2/λ follows. Symbol for symbol, this is the RP9 analysis with λt in place of t/RC.

The half-life sets the applications. Radioactive waste must be stored securely for many half-lives of its longest-lived components, which for some isotopes means centuries. Dating runs the clock backwards: living things hold a known fraction of carbon-14, so the fraction remaining in a bone, with T½ = 5730 years, dates its death.

Which nuclei decay, and how

Plot every stable nuclide as a point with proton number Z across and neutron number N up, and they hug a narrow stable band: N roughly equal to Z for light nuclei, bending neutron-rich as Z grows, because extra neutrons add strong-force glue without adding proton repulsion.

The N against Z map of the nuclides: a stable band bending above the N equals Z line, with each decay mode stepping unstable nuclei back towards itneutron-rich: β⁻ makes n into pproton-rich: β⁺ or electron capturestable bandN = Zαβ⁻β⁺proton number Zneutron number N
FIG. 3The N against Z map: each decay mode steps an unstable nucleus back towards the stable band.

Position on the map predicts the decay. Neutron-rich nuclei, above the band, undergo β⁻ decay: a neutron becomes a proton, so N falls by 1 and Z rises by 1. ⁹⁰Sr becomes ⁹⁰Y (Z: 38 to 39) plus e⁻ and an antineutrino νe. Proton-rich nuclei, below the band, go the other way by β⁺ decay or electron capture, each turning a proton into a neutron. The heaviest nuclei shed bulk by α decay: ²²⁶Ra becomes ²²²Rn (Z: 88 to 86) plus ⁴He, dropping A by 4 and Z by 2. In every equation, A and Z balance across the arrow.

Decay often leaves the daughter in an excited state: nuclei have energy levels like atoms, drawn as nuclear energy level diagrams, and the drop to the ground state emits a γ photon. Medicine exploits one such state deliberately. Technetium-99m is a long-lived excited state that emits gamma alone, with a six hour half-life: injected as a tracer, its photons escape the body to a camera, and the source is gone by the next day.

THE EXAM BIT

  • The word random earns its mark with a definition: constant probability of decay per nucleus per unit time, unaffected by conditions. Say probability, not chance it might happen.
  • Convert mass to nuclei via moles: divide by molar mass, multiply by the Avogadro constant. Grams and kilograms trip this chain; the booklet's Nₐ is per mole.
  • Half-life from a log graph: the gradient is −λ, so read its magnitude and use T½ = ln 2/λ. Quote the straightness of the line as your evidence the decay is exponential.
  • Decay equations balance twice: nucleon numbers across the top, proton numbers across the bottom, with the antineutrino written in for β⁻.
  • Technetium-99m answers want three properties: gamma only, so it leaves the body without heavy ionisation; a six hour half-life, long enough to image, short enough to clear; and emission from an excited nuclear state.

CHECK YOURSELF

Caesium-137 has a half-life of 30 years. A sealed source contains 3.0 μg of caesium-137 (molar mass 137 g mol⁻¹). Find the decay constant and the activity of the source. Take 1 year = 3.15 × 10⁷ s.

Show a hint

Half-life to λ first; then mass to moles to nuclei; then A = λN.

Show the answer

T½ = 30 × 3.15 × 107 = 9.45 × 108 s, so λ = ln 2 / 9.45 × 108 = 7.3 × 10-10 s-1.

N = (3.0 × 10-6 / 137) × 6.02 × 1023 = 1.3 × 1016 nuclei.

A = λN = 7.3 × 10-10 × 1.3 × 1016 = 9.7 × 106 Bq: ten million decays a second from three millionths of a gram.

One nucleus is a coin toss; a mole of them is a clock.

Every half-life keeps the same fraction, so the count halves forever and never reaches zero.

No animated video for this topic yet; these notes stand alone. InkPhysics on YouTube.