Biology › Inheritance and population genetics › Meiosis: two divisions, and why no two gametes come out the same
Meiosis: two divisions, and why no two gametes come out the same
Mitosis makes copies. Meiosis does the opposite job on purpose: it halves the chromosome number and shuffles the deck twice on the way, so that four cells leave a division that started with one, and no two of them carry the same set of alleles.
Before this The cell cycle and mitosis · DNA structure and replication · Eukaryotic cell ultrastructure
Before you start
Meiosis is mitosis done twice, so learning it means learning the same four stages again with roman numerals attached. Half of that is fair: the second division really is mitosis in miniature, chromatid for chromatid. The first division has no counterpart anywhere in mitosis. Homologous chromosomes find each other, exchange lengths of DNA, and then separate as whole chromosomes with their centromeres intact — three things mitosis never does. Every ratio you will meet later in this unit comes out of that one division.
What you should be able to do
- Say which chromosomes separate in the first division and which in the second, and why that order matters.
- Describe how a bivalent forms and what crossing over does to the chromatids in it.
- Work out how many chromosome combinations a gamete could carry, given the haploid number.
- Track chromosome number and chromatid number through both divisions without losing count.
- Set out the differences between mitosis and meiosis in terms an examiner can mark.
The division that has no equivalent in mitosis
A body cell of yours carries 46 chromosomes, and they are not 46 unrelated objects. They are 23 homologous pairs: two copies of chromosome 1, two of chromosome 2, and so on, one member of each pair inherited from each of your parents. The two members of a pair are the same length, carry the same genes in the same order, and differ only in which alleles sit at those loci. Mitosis takes no notice of the pairing at all. Meiosis is built around it.
The problem meiosis solves is arithmetical. If a sperm carrying 46 chromosomes fertilised an egg carrying 46, the zygote would have 92, and its children 184. Gametes therefore have to be haploid: one chromosome from each pair, 23 in total. Halving the number is not a matter of throwing chromosomes away at random — a gamete missing chromosome 7 and carrying two copies of chromosome 12 is no use to anyone. Each gamete needs exactly one representative of each pair, and the only reliable way to arrange that is to line the pairs up and pull them apart.
DNA replication happens once, in the interphase before meiosis begins, and not again between the two divisions. So a cell entering meiosis has 46 chromosomes and 92 chromatids; the cells leaving meiosis I have 23 chromosomes and 46 chromatids each; the four cells leaving meiosis II have 23 chromosomes and 23 chromatids each. The chromosome number halves at the first division and the DNA content halves at both.
- Homologous pair
- Two chromosomes of the same length carrying the same genes at the same loci, one from each parent, though not necessarily the same alleles.
- Diploid
- Having chromosomes in homologous pairs, written 2n.
- Haploid
- Having one chromosome from each homologous pair, written n.
- Bivalent
- The structure formed when a homologous pair comes together in prophase I: two chromosomes, four chromatids.
- Reduction division
- A division that halves the chromosome number. Meiosis I is one; meiosis II is not.
Prophase I: pairing, and the exchange that follows
Prophase I is the longest and the most eventful stage in the whole process. The chromosomes condense as they do in mitosis, but then something else happens: each chromosome finds its homologue and the two lie down alongside each other along their whole length. That pairing is called synapsis, and the paired structure is a bivalent. Because both chromosomes were replicated in interphase, a bivalent contains four chromatids, which is why some books call it a tetrad.
Lying that close, chromatids break and rejoin. A chromatid of the maternal chromosome and a chromatid of the paternal chromosome — non-sister chromatids, and the word non-sister is worth a mark on its own — break at the same point and each joins to the other's cut end. The point where they cross is a chiasma, plural chiasmata, and it is visible down a good microscope. When the bivalent later comes apart, the two chromatids that took part leave carrying a stretch of DNA from the other parent's chromosome.
The consequence is easy to state and easy to underrate: after crossing over, sister chromatids are no longer genetically identical. Everything you learned about mitosis assumed they were. Here, a chromatid can carry the maternal allele of one gene and the paternal allele of a gene further along the same chromosome — a combination that existed on neither chromosome the cell started with. Crossing over is the only mechanism in meiosis that makes new combinations of alleles within a chromosome, and it is what stops genes on the same chromosome being locked together for ever.
- Crossing over
- The exchange of equivalent sections of DNA between non-sister chromatids of a homologous pair during prophase I.
- Chiasma
- The visible point at which two non-sister chromatids cross during a bivalent's crossover.
- Recombinant
- A chromatid, or an offspring, carrying a combination of alleles that neither parental chromosome carried.
Metaphase I, and an arithmetic worth doing
At metaphase I the bivalents move to the equator, and this is where the second source of variation appears. Each bivalent settles with one member facing one pole and the other facing the opposite pole, and which member faces which pole is decided independently for every bivalent. That is independent assortment. Nothing keeps the chromosomes you inherited from your mother together; they are dealt out pair by pair, and each deal is a fresh coin toss.
number of chromosome combinations in a gamete = 2nn is the haploid number: the number of homologous pairs. Crossing over is not included in this count, and makes the true figure much larger.
With n = 23, that is 223 = 8 388 608 different chromosome combinations a single human gamete could carry. Fertilisation is random, so any one of those sperm could meet any one of those eggs: 223 × 223 = 246, or about 7 × 1013 different zygotes from one couple, before crossing over is allowed to complicate anything. The number is not the point; the reason it gets that large from such a simple mechanism is.
One subtlety, in case a question asks for the number of arrangements rather than the number of gametes. A bivalent that sits with the maternal chromosome facing left produces the same pair of daughter cells as one facing right with the whole plate mirrored, so the number of genuinely distinct metaphase I arrangements is 2n−1. Each arrangement sends a different combination to each of the two poles, so 2n−1 arrangements still give 2n kinds of gamete. Answer whichever the question asked for, and say which you have counted.
Counting combinations in a fruit fly
A fruit fly has a diploid number of 8. Calculate the number of different chromosome combinations possible in its gametes, and the number possible in a zygote formed by two such flies. Ignore crossing over.
Diploid number 8 means four homologous pairs, so n = 4 and the number of gamete combinations is 24 = 16.
A zygote takes one gamete from each parent, and the two choices are independent, so 16 × 16 = 256.
The trap is using 8 rather than 4 as n. The exponent counts pairs, not chromosomes, because it is one coin toss per pair. If the question gives you the diploid number, halve it before you do anything else.
The second division, and keeping count
Meiosis II starts with two haploid cells whose chromosomes are still two chromatids each, and it does to them what mitosis would: chromosomes line up singly on a new equator, centromeres divide, chromatids are pulled apart. The outcome is four haploid cells. Because crossing over happened back in prophase I, the two cells produced from each meiosis I product need not be identical to each other either.
Counting is where marks are lost, so it is worth a table. Take a cell with a diploid number of 8.
| Stage | Chromosomes per cell | Chromatids per cell | Cells |
|---|---|---|---|
| Before meiosis, after replication | 8 | 16 | 1 |
| End of meiosis I | 4 | 8 | 2 |
| End of meiosis II | 4 | 4 | 4 |
The chromosome number halves once, at the first division. The chromatid number halves twice — once because the cell divides in two and once because the centromeres finally split. A cell at the end of meiosis I is already haploid, even though it contains as much DNA as an unreplicated diploid cell, and that pair of facts is what makes questions using DNA mass against time so effective at separating candidates.
Set against mitosis, which you have already met, the differences line up cleanly. Learn them as a table rather than as prose, because that is the form the question takes.
| Mitosis | Meiosis | |
|---|---|---|
| Divisions | One | Two |
| Daughter cells | Two | Four |
| Chromosome number | Unchanged: diploid to diploid | Halved: diploid to haploid |
| Homologues pair up? | No | Yes, as bivalents in prophase I |
| Crossing over | No | Yes, in prophase I |
| Genetic result | Daughters identical to the parent cell | All four daughters different |
| Where it happens | Growth, repair, asexual reproduction | Formation of gametes, or of spores in plants and fungi |
Three sources of variation, and one way it goes wrong
Sexual reproduction generates variation at three points, and a question asking you to explain how meiosis produces genetic variation is asking for the first two by name, with the third as a bonus if the wording allows it.
Crossing over in prophase I makes new combinations of alleles along a single chromosome. Independent assortment at metaphase I makes new combinations of whole chromosomes. Random fertilisation then combines any one gamete with any other, which is not part of meiosis but is part of the answer whenever the question says sexual reproduction rather than meiosis. Mutation supplies the alleles that all three of these shuffle, but it is a separate process and claiming it as a product of meiosis will not score.
Occasionally the machinery fails. If a homologous pair does not separate at anaphase I, or a pair of sister chromatids does not separate at anaphase II, the result is non-disjunction: gametes with one chromosome too many and gametes with one too few. A zygote formed from a gamete carrying an extra chromosome 21 has three copies of it, which is the origin of Down syndrome. The same failure at anaphase II affects only two of the four products rather than all four, which is a distinction some specifications ask you to draw.
TRY IT — Explaining an unexpected count
A plant cell with a diploid number of 12 undergoes meiosis. One of the four resulting cells is found to contain 7 chromosomes. Explain how this could have happened, and state the chromosome numbers you would expect in the other three cells.
Check your answer
Non-disjunction has occurred: a pair of chromosomes has failed to separate, so one cell received both members of that pair and another received neither.
The normal haploid number is 6. A cell with 7 has one extra, so one other cell has 5. Whether the remaining two cells are affected tells you when it happened: if the failure was at anaphase I, all four cells are abnormal and the counts are 7, 7, 5, 5. If it was at anaphase II, only the two products of the affected cell are wrong, so the counts are 7, 5, 6, 6.
Most candidates get the non-disjunction and stop there. Naming which anaphase, and giving the four numbers it implies, is what turns two marks into four.
In the exam
- Homologous chromosomes separate in meiosis I; sister chromatids separate in meiosis II. Almost every mark on this topic hangs off getting those two the right way round.
- Crossing over is between non-sister chromatids of a homologous pair. Writing 'between chromatids' loses the mark because sister chromatids are identical and swapping between them changes nothing.
- For the number of gamete combinations, the exponent is the number of pairs. Halve the diploid number first, every time.
- A cell at the end of meiosis I is haploid but its chromosomes are still two chromatids each. Questions plotting DNA content against time are testing exactly that.
- If a question says 'explain how meiosis produces genetic variation', give crossing over and independent assortment and name the stage each happens in. Random fertilisation belongs in the answer only when the question says sexual reproduction.
Check yourself
A mouse has a diploid number of 40. State the number of chromosomes and the number of chromatids in one cell at the end of meiosis I, and in one cell at the end of meiosis II. Then state how many different chromosome combinations its gametes could carry, ignoring crossing over, and explain where that number comes from.
Answer
At the end of meiosis I each cell has 20 chromosomes and 40 chromatids. The homologous pairs have separated, so the chromosome number has halved, but the centromeres have not divided and each chromosome is still two chromatids.
At the end of meiosis II each cell has 20 chromosomes and 20 chromatids. The centromeres have now divided and the sister chromatids have gone to opposite poles, so each is a chromosome in its own right.
A diploid number of 40 means 20 homologous pairs, so n = 20 and the number of combinations is 220 = 1 048 576.
The exponent is 20 rather than 40 because each homologous pair is decided once, at metaphase I, and the pairs are decided independently of one another. Twenty independent two-way choices give 220 outcomes.
Questions
Question 14 marks
Describe how crossing over happens during prophase I of meiosis, and describe its effect on the chromatids involved.
Mark scheme
- B1 each chromosome finds its homologue and the two lie alongside each other along their whole length, forming a bivalent of four chromatids
- B1 non-sister chromatids, one maternal and one paternal, break at the same point and each joins to the other's cut end
- B1 the visible point at which they cross is a chiasma, and equivalent sections of DNA have been exchanged
- A1 the two chromatids that took part leave carrying a combination of alleles that neither parental chromosome had, so sister chromatids are no longer genetically identical; the other two leave unchanged
Question 24 marks
Explain how meiosis produces gametes that are genetically different from one another, naming the stage at which each process happens.
Mark scheme
- B1 crossing over in prophase I exchanges sections of DNA between non-sister chromatids of a homologous pair
- B1 this makes new combinations of alleles along a single chromosome, combinations that were on neither chromosome the cell started with
- B1 independent assortment at metaphase I decides which member of each bivalent faces which pole, and the decision is made separately for every bivalent
- A1 this makes new combinations of whole chromosomes, giving 2 to the power n kinds of gamete where n is the number of homologous pairs
Question 34 marks
A species of plant has a diploid number of 14. Calculate the number of different chromosome combinations its gametes could carry from independent assortment alone, and calculate the number of different chromosome combinations possible in a zygote formed by two such plants.
Mark scheme
- M1 halve the diploid number to get the number of homologous pairs, so n = 7, because one decision is made per pair
- A1 2 to the power 7 is 128 chromosome combinations in a gamete
- M1 a zygote takes one gamete from each parent and the two are independent, so multiply 128 by 128
- A1 16 384 combinations, and crossing over would make the true figure larger still
Question 44 marks
Compare mitosis with meiosis, referring to the number of divisions, the chromosome number of the daughter cells, the behaviour of homologous chromosomes and the genetic result.
Mark scheme
- B1 mitosis is one division producing two daughter cells, whereas meiosis is two divisions producing four
- B1 mitosis leaves the chromosome number unchanged, diploid to diploid, whereas meiosis halves it, diploid to haploid
- B1 homologous chromosomes do not pair in mitosis, whereas in meiosis they pair as bivalents in prophase I and cross over
- B1 the daughters of mitosis are genetically identical to the parent cell, whereas the four products of meiosis all differ from one another
Question 53 marks
A chemical prevents chiasmata from forming in prophase I but allows the rest of meiosis to run normally. Suggest what this does to the genetic variation of the gametes produced, and suggest why they would still not all be the same.
Mark scheme
- B1 no crossing over would occur, so no new combinations of alleles would be made along a chromosome and each chromatid would carry the alleles of the parental chromosome it came from
- B1 sister chromatids would therefore stay genetically identical, so the two cells produced by each meiosis II would be identical to each other
- A1 independent assortment at metaphase I would still combine whole chromosomes in new ways, giving 2 to the power n kinds of gamete, so variation would be reduced rather than abolished
Question 62 marks
State the stage of meiosis at which homologous chromosomes are separated, and state the stage at which sister chromatids are separated.
Mark scheme
- B1 homologous chromosomes are separated at anaphase I
- B1 sister chromatids are separated at anaphase II, when the centromeres divide
Worth remembering
- One replication, two divisions, four haploid cells.
- Meiosis I separates homologues and halves the chromosome number; meiosis II separates chromatids and does not.
- Crossing over happens in prophase I, between non-sister chromatids, and makes sister chromatids no longer identical.
- Independent assortment happens at metaphase I and gives 2 to the power n combinations, where n is the number of pairs.
- Non-disjunction at anaphase I affects all four products; at anaphase II it affects two.