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Exponential functions and e questions
Put x in the exponent and everything changes. Equal steps in x now multiply y instead of adding to it. Among all the possible bases one is special, because the curve of e to the x climbs at a rate equal to its own height, and that single property is why the same number keeps turning up in banking, biology and radioactive decay.
7 original questions · 21 marks · the exponential functions and e notes · Exponentials and logarithms
Every question here is written for this library rather than taken from a past paper. Write your answer out before opening the worked one: the answers award marks point by point, and the marks are easier to see when you have something of your own to compare against.
For the curve y = 3x, write down the y-intercept, the value of y at x = 2, and the equation of the asymptote.
Worked answer
The intercept is (0, 1), since 30 = 1. At x = 2, y = 9. The asymptote is y = 0, the x-axis, which the curve approaches on the left without ever touching. B1 B1 B1 for the three answers. Every curve y = ax passes through (0, 1) whatever a is, so that intercept is worth remembering rather than working out.Explain why the equation 5x = 0 has no solution.
Worked answer
Every exponential is positive everywhere: 5x takes every value above zero and no others. The curve hugs the x-axis as x heads left but never reaches it, so zero is approached, not achieved. B1 for the range being strictly positive, B1 for the asymptote argument.For the curve y = e4x, write down the gradient function, the gradient at x = 0, and the gradient at x = 0.5 to 3 significant figures.
Worked answer
Differentiating ekx multiplies by k, so the gradient function is 4e4x. At x = 0 the gradient is 4e0 = 4, and at x = 0.5 it is 4e2 = 29.6 to 3 significant figures, four times the height there. B1 for the gradient function, B1 for 4, B1 for 29.6. The factor of 4 is the only mark at risk; writing e4x unchanged is the error the chain rule exists to prevent.For the curve y = e−2x, write down the gradient function and the value of y at x = 1, and describe the curve's behaviour as x grows.
Worked answer
The gradient function is −2e−2x, negative everywhere: the curve falls at every point. At x = 1, y = e−2 = 0.135 to 3 significant figures. As x grows the curve decays towards the asymptote y = 0, steeply at first and ever more gently. B1 for the gradient function, B1 for 0.135, B1 for the decay to the asymptote.A population of bacteria triples every hour, starting from 500. Write down a model for the population P after t hours, and find the population after 4 hours.
Worked answer
P = 500 × 3t, since each unit step in t multiplies the population by the same ratio 3. After 4 hours, P = 500 × 81 = 40 500. B1 for the model, M1 for substituting t = 4, A1 for the value after four hours. The starting value belongs in front and the growth factor in the base, so P = 500t3 or P = 3 × 500t both fail the first check, which is that P = 500 at t = 0.For y = 5e0.2x, show that the gradient at every point equals 0.2y, and find the height and gradient at x = 5, each to 3 significant figures.
Worked answer
The gradient function is 5 × 0.2e0.2x = 0.2 × 5e0.2x = 0.2y: the rate of change is proportional to the amount, with constant 0.2. At x = 5 the height is 5e = 13.6 and the gradient is 0.2 × 5e = e = 2.72. M1 for differentiating, A1 for the link to 0.2y, A1 for 13.6, A1 for 2.72. This proportionality is the property that makes e the modelling base.The curves y = 2x and y = 3x have gradients of about 0.69 and 1.10 at their common point (0, 1). Explain what this suggests about the number e, and state the defining property of y = ex.
Worked answer
A gradient of exactly 1 at (0, 1) must belong to some base between 2 and 3, and that base is e = 2.718…. The defining property is that y = ex is its own gradient function: at every point the gradient equals the height, and (0, 1) is only the most convenient place to notice it. B1 for the base lying between 2 and 3, B1 for e = 2.718, B1 for the self-derivative property.
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